Distance from Waterbury to Wielsbeke
The shortest distance (air line) between Waterbury and Wielsbeke is 3,541.76 mi (5,699.91 km).
How far is Waterbury from Wielsbeke
Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 16:46 (09.03.2025)
Wielsbeke is located in Arr. Tielt, Belgium within 50° 54' 32.04" N 3° 22' 10.92" E (50.9089, 3.3697) coordinates. The local time in Wielsbeke is 22:46 (09.03.2025)
The calculated flying distance from Wielsbeke to Wielsbeke is 3,541.76 miles which is equal to 5,699.91 km.
Waterbury, Connecticut, United States
Related Distances from Waterbury
Wielsbeke, Arr. Tielt, Belgium