Distance from Waukee to Bad Sassendorf
The shortest distance (air line) between Waukee and Bad Sassendorf is 4,488.78 mi (7,224.00 km).
How far is Waukee from Bad Sassendorf
Waukee is located in Iowa, United States within 41° 35' 54.6" N -94° 6' 47.16" W (41.5985, -93.8869) coordinates. The local time in Waukee is 23:49 (05.03.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 06:49 (06.03.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,488.78 miles which is equal to 7,224.00 km.
Related Distances from Waukee
Bad Sassendorf, Soest, Germany