Distance from Waukegan to Bad Sooden-Allendorf
The shortest distance (air line) between Waukegan and Bad Sooden-Allendorf is 4,314.24 mi (6,943.09 km).
How far is Waukegan from Bad Sooden-Allendorf
Waukegan is located in Illinois, United States within 42° 22' 11.28" N -88° 7' 42.24" W (42.3698, -87.8716) coordinates. The local time in Waukegan is 23:53 (05.03.2025)
Bad Sooden-Allendorf is located in Werra-Meißner-Kreis, Germany within 51° 16' 59.88" N 9° 58' 59.88" E (51.2833, 9.9833) coordinates. The local time in Bad Sooden-Allendorf is 06:53 (06.03.2025)
The calculated flying distance from Bad Sooden-Allendorf to Bad Sooden-Allendorf is 4,314.24 miles which is equal to 6,943.09 km.
Waukegan, Illinois, United States
Related Distances from Waukegan
Bad Sooden-Allendorf, Werra-Meißner-Kreis, Germany