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      Distance from Waukegan to Saint-Andre-les-Vergers

      The shortest distance (air line) between Waukegan and Saint-Andre-les-Vergers is 4,207.08 mi (6,770.64 km).

      How far is Waukegan from Saint-Andre-les-Vergers

      Waukegan is located in Illinois, United States within 42° 22' 11.28" N -88° 7' 42.24" W (42.3698, -87.8716) coordinates. The local time in Waukegan is 04:33 (04.03.2025)

      Saint-Andre-les-Vergers is located in Aube, France within 48° 16' 46.92" N 4° 3' 14.04" E (48.2797, 4.0539) coordinates. The local time in Saint-Andre-les-Vergers is 11:33 (04.03.2025)

      The calculated flying distance from Saint-Andre-les-Vergers to Saint-Andre-les-Vergers is 4,207.08 miles which is equal to 6,770.64 km.

      Waukegan, Illinois, United States

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      Saint-Andre-les-Vergers, Aube, France

      Related Distances to Saint-Andre-les-Vergers