Distance from Waukegan to Sendenhorst
The shortest distance (air line) between Waukegan and Sendenhorst is 4,215.69 mi (6,784.49 km).
How far is Waukegan from Sendenhorst
Waukegan is located in Illinois, United States within 42° 22' 11.28" N -88° 7' 42.24" W (42.3698, -87.8716) coordinates. The local time in Waukegan is 18:40 (12.03.2025)
Sendenhorst is located in Warendorf, Germany within 51° 50' 38.04" N 7° 49' 40.08" E (51.8439, 7.8278) coordinates. The local time in Sendenhorst is 01:40 (13.03.2025)
The calculated flying distance from Sendenhorst to Sendenhorst is 4,215.69 miles which is equal to 6,784.49 km.
Waukegan, Illinois, United States
Related Distances from Waukegan
Sendenhorst, Warendorf, Germany