Distance from Waukegan to Sint-Andries
The shortest distance (air line) between Waukegan and Sint-Andries is 4,068.90 mi (6,548.27 km).
How far is Waukegan from Sint-Andries
Waukegan is located in Illinois, United States within 42° 22' 11.28" N -88° 7' 42.24" W (42.3698, -87.8716) coordinates. The local time in Waukegan is 13:44 (26.02.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 20:44 (26.02.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 4,068.90 miles which is equal to 6,548.27 km.
Waukegan, Illinois, United States
Related Distances from Waukegan
Sint-Andries, Arr. Brugge, Belgium