Distance from Waukegan to Sint-Kruis
The shortest distance (air line) between Waukegan and Sint-Kruis is 4,070.98 mi (6,551.62 km).
How far is Waukegan from Sint-Kruis
Waukegan is located in Illinois, United States within 42° 22' 11.28" N -88° 7' 42.24" W (42.3698, -87.8716) coordinates. The local time in Waukegan is 22:26 (26.04.2025)
Sint-Kruis is located in Arr. Brugge, Belgium within 51° 12' 42.12" N 3° 15' 0" E (51.2117, 3.2500) coordinates. The local time in Sint-Kruis is 05:26 (27.04.2025)
The calculated flying distance from Sint-Kruis to Sint-Kruis is 4,070.98 miles which is equal to 6,551.62 km.
Waukegan, Illinois, United States
Related Distances from Waukegan
Sint-Kruis, Arr. Brugge, Belgium