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      Distance from Waukegan to Soisy-sous-Montmorency

      The shortest distance (air line) between Waukegan and Soisy-sous-Montmorency is 4,113.23 mi (6,619.60 km).

      How far is Waukegan from Soisy-sous-Montmorency

      Waukegan is located in Illinois, United States within 42° 22' 11.28" N -88° 7' 42.24" W (42.3698, -87.8716) coordinates. The local time in Waukegan is 11:22 (04.03.2025)

      Soisy-sous-Montmorency is located in Val-d’Oise, France within 48° 59' 16.08" N 2° 17' 58.92" E (48.9878, 2.2997) coordinates. The local time in Soisy-sous-Montmorency is 18:22 (04.03.2025)

      The calculated flying distance from Soisy-sous-Montmorency to Soisy-sous-Montmorency is 4,113.23 miles which is equal to 6,619.60 km.

      Waukegan, Illinois, United States

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      Soisy-sous-Montmorency, Val-d’Oise, France

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