Distance from Waukegan to Steenokkerzeel
The shortest distance (air line) between Waukegan and Steenokkerzeel is 4,128.26 mi (6,643.80 km).
How far is Waukegan from Steenokkerzeel
Waukegan is located in Illinois, United States within 42° 22' 11.28" N -88° 7' 42.24" W (42.3698, -87.8716) coordinates. The local time in Waukegan is 17:02 (26.02.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 00:02 (27.02.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 4,128.26 miles which is equal to 6,643.80 km.
Waukegan, Illinois, United States
Related Distances from Waukegan
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium