Distance from Waukegan to Vetraz-Monthoux
The shortest distance (air line) between Waukegan and Vetraz-Monthoux is 4,373.34 mi (7,038.22 km).
How far is Waukegan from Vetraz-Monthoux
Waukegan is located in Illinois, United States within 42° 22' 11.28" N -88° 7' 42.24" W (42.3698, -87.8716) coordinates. The local time in Waukegan is 14:47 (04.03.2025)
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 21:47 (04.03.2025)
The calculated flying distance from Vetraz-Monthoux to Vetraz-Monthoux is 4,373.34 miles which is equal to 7,038.22 km.
Waukegan, Illinois, United States
Related Distances from Waukegan
Vetraz-Monthoux, Haute-Savoie, France