Distance from Waunakee to Sveti Ivan Zelina
The shortest distance (air line) between Waunakee and Sveti Ivan Zelina is 4,782.27 mi (7,696.32 km).
How far is Waunakee from Sveti Ivan Zelina
Waunakee is located in Wisconsin, United States within 43° 10' 58.44" N -90° 33' 19.08" W (43.1829, -89.4447) coordinates. The local time in Waunakee is 00:59 (27.02.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 07:59 (27.02.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,782.27 miles which is equal to 7,696.32 km.
Waunakee, Wisconsin, United States
Related Distances from Waunakee
Sveti Ivan Zelina, Zagrebačka županija, Croatia