Distance from Wheaton to San Lazzaro di Savena
The shortest distance (air line) between Wheaton and San Lazzaro di Savena is 4,676.97 mi (7,526.85 km).
How far is Wheaton from San Lazzaro di Savena
Wheaton is located in Illinois, United States within 41° 51' 21.96" N -89° 53' 29.4" W (41.8561, -88.1085) coordinates. The local time in Wheaton is 20:12 (27.03.2025)
San Lazzaro di Savena is located in Bologna, Italy within 44° 28' 17.76" N 11° 24' 17.64" E (44.4716, 11.4049) coordinates. The local time in San Lazzaro di Savena is 03:12 (28.03.2025)
The calculated flying distance from San Lazzaro di Savena to San Lazzaro di Savena is 4,676.97 miles which is equal to 7,526.85 km.
Wheaton, Illinois, United States
Related Distances from Wheaton
San Lazzaro di Savena, Bologna, Italy