Distance from Wielsbeke to Jefferson Hills
The shortest distance (air line) between Wielsbeke and Jefferson Hills is 3,874.83 mi (6,235.94 km).
How far is Wielsbeke from Jefferson Hills
Wielsbeke is located in Arr. Tielt, Belgium within 50° 54' 32.04" N 3° 22' 10.92" E (50.9089, 3.3697) coordinates. The local time in Wielsbeke is 10:52 (14.12.2025)
Jefferson Hills is located in Pennsylvania, United States within 40° 17' 33.36" N -80° 4' 1.56" W (40.2926, -79.9329) coordinates. The local time in Jefferson Hills is 04:52 (14.12.2025)
The calculated flying distance from Jefferson Hills to Jefferson Hills is 3,874.83 miles which is equal to 6,235.94 km.
Wielsbeke, Arr. Tielt, Belgium
Related Distances from Wielsbeke
Jefferson Hills, Pennsylvania, United States