Distance from Williamsburg to Scherpenheuvel
The shortest distance (air line) between Williamsburg and Scherpenheuvel is 3,945.45 mi (6,349.59 km).
How far is Williamsburg from Scherpenheuvel
Williamsburg is located in Virginia, United States within 37° 16' 9.48" N -77° 17' 32.64" W (37.2693, -76.7076) coordinates. The local time in Williamsburg is 23:36 (04.03.2025)
Scherpenheuvel is located in Arr. Leuven, Belgium within 51° 0' 37.08" N 4° 58' 22.08" E (51.0103, 4.9728) coordinates. The local time in Scherpenheuvel is 05:36 (05.03.2025)
The calculated flying distance from Scherpenheuvel to Scherpenheuvel is 3,945.45 miles which is equal to 6,349.59 km.
Williamsburg, Virginia, United States
Related Distances from Williamsburg
Scherpenheuvel, Arr. Leuven, Belgium