Distance from Williamsburg to Steenokkerzeel
The shortest distance (air line) between Williamsburg and Steenokkerzeel is 3,928.66 mi (6,322.57 km).
How far is Williamsburg from Steenokkerzeel
Williamsburg is located in Virginia, United States within 37° 16' 9.48" N -77° 17' 32.64" W (37.2693, -76.7076) coordinates. The local time in Williamsburg is 14:39 (05.03.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 20:39 (05.03.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 3,928.66 miles which is equal to 6,322.57 km.
Williamsburg, Virginia, United States
Related Distances from Williamsburg
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium