Distance from Woodinville to Bad Sassendorf
The shortest distance (air line) between Woodinville and Bad Sassendorf is 4,971.61 mi (8,001.03 km).
How far is Woodinville from Bad Sassendorf
Woodinville is located in Washington, United States within 47° 45' 25.2" N -123° 51' 8.28" W (47.7570, -122.1477) coordinates. The local time in Woodinville is 14:19 (06.03.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 23:19 (06.03.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,971.61 miles which is equal to 8,001.03 km.
Woodinville, Washington, United States
Related Distances from Woodinville
Bad Sassendorf, Soest, Germany