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      Distance from Woodinville to Sint-Pieters-Leeuw

      The shortest distance (air line) between Woodinville and Sint-Pieters-Leeuw is 4,923.33 mi (7,923.33 km).

      How far is Woodinville from Sint-Pieters-Leeuw

      Woodinville is located in Washington, United States within 47° 45' 25.2" N -123° 51' 8.28" W (47.7570, -122.1477) coordinates. The local time in Woodinville is 17:32 (12.06.2025)

      Sint-Pieters-Leeuw is located in Arr. Halle-Vilvoorde, Belgium within 50° 46' 59.88" N 4° 15' 0" E (50.7833, 4.2500) coordinates. The local time in Sint-Pieters-Leeuw is 02:32 (13.06.2025)

      The calculated flying distance from Sint-Pieters-Leeuw to Sint-Pieters-Leeuw is 4,923.33 miles which is equal to 7,923.33 km.

      Woodinville, Washington, United States

      Related Distances from Woodinville

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      Woodinville to New York (New York)2,396.55 mi (3,856.87 km)
      Woodinville to Brooklyn (New York)2,396.86 mi (3,857.37 km)
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      Sint-Pieters-Leeuw, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Pieters-Leeuw