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      Distance from Yankton to Sint-Genesius-Rode

      The shortest distance (air line) between Yankton and Sint-Genesius-Rode is 4,446.97 mi (7,156.71 km).

      How far is Yankton from Sint-Genesius-Rode

      Yankton is located in South Dakota, United States within 42° 53' 24.36" N -98° 36' 26.28" W (42.8901, -97.3927) coordinates. The local time in Yankton is 16:01 (06.06.2025)

      Sint-Genesius-Rode is located in Arr. Halle-Vilvoorde, Belgium within 50° 44' 42" N 4° 20' 47.04" E (50.7450, 4.3464) coordinates. The local time in Sint-Genesius-Rode is 23:01 (06.06.2025)

      The calculated flying distance from Sint-Genesius-Rode to Sint-Genesius-Rode is 4,446.97 miles which is equal to 7,156.71 km.

      Yankton, South Dakota, United States

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      Yankton to Boston (Massachusetts)1,333.01 mi (2,145.28 km)
      Yankton to San Francisco (California)1,360.88 mi (2,190.13 km)
      Yankton to Miami (Florida)1,529.18 mi (2,460.98 km)
      Yankton to Minneapolis (Minnesota)250.26 mi (402.76 km)
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      Sint-Genesius-Rode, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Genesius-Rode