Distance from Zonnebeke to Cesky Tesin
The shortest distance (air line) between Zonnebeke and Cesky Tesin is 693.30 mi (1,115.76 km).
How far is Zonnebeke from Cesky Tesin
Zonnebeke is located in Arr. Ieper, Belgium within 50° 52' 0.12" N 2° 58' 59.88" E (50.8667, 2.9833) coordinates. The local time in Zonnebeke is 07:00 (01.12.2024)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 07:00 (01.12.2024)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 693.30 miles which is equal to 1,115.76 km.
Zonnebeke, Arr. Ieper, Belgium
Related Distances from Zonnebeke
Cesky Tesin, Moravskoslezský kraj, Czechia