Distance from Zonnebeke to Secaucus
The shortest distance (air line) between Zonnebeke and Secaucus is 3,602.43 mi (5,797.54 km).
How far is Zonnebeke from Secaucus
Zonnebeke is located in Arr. Ieper, Belgium within 50° 52' 0.12" N 2° 58' 59.88" E (50.8667, 2.9833) coordinates. The local time in Zonnebeke is 20:30 (16.12.2025)
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 14:30 (16.12.2025)
The calculated flying distance from Secaucus to Secaucus is 3,602.43 miles which is equal to 5,797.54 km.
Zonnebeke, Arr. Ieper, Belgium
Related Distances from Zonnebeke
Secaucus, New Jersey, United States