Distance from Zonnebeke to Seymour
The shortest distance (air line) between Zonnebeke and Seymour is 4,158.20 mi (6,691.97 km).
How far is Zonnebeke from Seymour
Zonnebeke is located in Arr. Ieper, Belgium within 50° 52' 0.12" N 2° 58' 59.88" E (50.8667, 2.9833) coordinates. The local time in Zonnebeke is 21:18 (16.12.2025)
Seymour is located in Indiana, United States within 38° 56' 51.36" N -86° 6' 32.04" W (38.9476, -85.8911) coordinates. The local time in Seymour is 15:18 (16.12.2025)
The calculated flying distance from Seymour to Seymour is 4,158.20 miles which is equal to 6,691.97 km.
Zonnebeke, Arr. Ieper, Belgium
Related Distances from Zonnebeke
Seymour, Indiana, United States