Distance from San Diego to Warrensville Heights
The shortest distance (air line) between San Diego and Warrensville Heights is 2,033.01 mi (3,271.81 km).
How far is San Diego from Warrensville Heights
San Diego is located in California, United States within 32° 49' 52.68" N -118° 52' 40.08" W (32.8313, -117.1222) coordinates. The local time in San Diego is 23:50 (27.03.2025)
Warrensville Heights is located in Ohio, United States within 41° 26' 10.68" N -82° 28' 40.08" W (41.4363, -81.5222) coordinates. The local time in Warrensville Heights is 02:50 (28.03.2025)
The calculated flying distance from Warrensville Heights to Warrensville Heights is 2,033.01 miles which is equal to 3,271.81 km.
San Diego, California, United States
Related Distances from San Diego
Warrensville Heights, Ohio, United States